SOLUTION: 1.) A store sells one type of candy for 4.00 per pound and another type for 10.00 per pound. If the store combines these two candies to produce an 18- pound mixture for 6.00 per po

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Question 890097: 1.) A store sells one type of candy for 4.00 per pound and another type for 10.00 per pound. If the store combines these two candies to produce an 18- pound mixture for 6.00 per pound, how many pound of the more expensive candy are needed?




Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Any question of this type can be understood and handled in the general manner shown here: Mixture: Two-Part, price or cost, both material amounts unknown - http://www.algebra.com/tutors/mixture-price-two-part-both-parts-unknown.lesson?content_action=show_dev

If put the actual given numbers into the equations, you would use
%284u%2B10v%29%2F18=6 and u%2Bv=18.
u = how much of the lower cost candy
v = how much of the higher cost candy

The rational equation can be simplified before using:
%282u%2B5v%29%2F18=3
highlight_green%282u%2B5v=54%29