SOLUTION: A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 2 pieces of candy at random. Find the probability of both being lemon.

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Question 890053: A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 2 pieces of candy at random. Find the probability of both being lemon.
Found 2 solutions by mathrocks2, MathTherapy:
Answer by mathrocks2(1) (Show Source):
You can put this solution on YOUR website!
First you add up all the pieces of candy that you have in the bag. 6+3+2=11. Now that you know you have 11 pieces of candy. Then you take 2/11 and times that answer by 100 so you have a percent. the answer should be 18%

Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!

A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 2 pieces of candy at random. Find the probability of both being lemon.

P(L & L) = P(L) * P(L)
P(1st being a lemon):
P(2nd being a lemon): , considering that the first candy chosen was a lemon.
P(L & L) = , or