SOLUTION: Binomial distribution
suppose that 50% of a population is left handed, find the probability that in a group of 50 individuals:
a. at most 5 are left handed.
b. at least 5 are le
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-> SOLUTION: Binomial distribution
suppose that 50% of a population is left handed, find the probability that in a group of 50 individuals:
a. at most 5 are left handed.
b. at least 5 are le
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Question 890018: Binomial distribution
suppose that 50% of a population is left handed, find the probability that in a group of 50 individuals:
a. at most 5 are left handed.
b. at least 5 are left handed. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Binomial distribution
suppose that 50% of a population is left handed, find the probability that in a group of 50 individuals:
a. at most 5 are left handed.
P(0<= x <=5) = binomcdf(50,0.5,5) = 0.000000002105
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b. at least 5 are left handed.
P(6<= x <=50) = 1 - P(0<= x <=5) = 0.999999....
Cheers,
Stan H.
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