SOLUTION: a number is 1/10 less than its multiplicative inverse .find the number

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Question 889867: a number is 1/10 less than its multiplicative inverse .find the number
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
n = 1/n - 1/10
n = (10 - n)/10n
10n^2 = 10 - n
10n^2 + n - 10 = 0

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a number is 1/10 less than its multiplicative inverse .find the number
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x = (1/x)-(1/10)
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10x^2 = 10 - x
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10x^2 + x - 10 = 0
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x = [-1 +- sqrt(1-4*10*-10)]/20
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x = [-1 +- sqrt(401)]/20
x = 0.95
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Cheers,
Stan H.
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