SOLUTION: Log8x+log4x+log2x=1 where x=64 is answer..what are the steps

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Question 889788: Log8x+log4x+log2x=1 where x=64 is answer..what are the steps
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Log8x+log4x+log2x=1 where x=64 is answer..what are the steps
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Log(512) + log(256) + log(128) = 1
It's not = 1