SOLUTION: Given that x^2=y^2 - 4xz, find the value of x when y=1 and z=3/8

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Question 889697: Given that x^2=y^2 - 4xz, find the value of x when y=1 and z=3/8
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Treat as a quadratic equation in the variable, x. Use the general solution and substitute the given values for y and z.

x%5E2%2B4xz-y%5E2=0
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x=%28-4z%2B-+sqrt%2816z%5E2%2B4%2Ay%5E2%29%29%2F%282%29
x=%28-4z%2B-+2sqrt%284z%5E2%2By%5E2%29%29%2F2
highlight%28x=-2z%2B-+sqrt%284z%5E2%2By%5E2%29%29.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Given that x^2=y^2 - 4xz, find the value of x when y=1 and z=3/8


x%5E2+=+y%5E2+-+4xz

x%5E2+=+1%5E2+-+4x%283%2F8%29 ------ Substituting 1 for y, and 3%2F8 for z

x%5E2+=+1+-+3x%2F2

2x%5E2+=+2+-+3x ------ Multiplying by LCD, 2

2x%5E2+%2B+3x+-+2+=+0

Solve for x

Then do a check!! 



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