SOLUTION: I am being asked to find one side of a rectangle when one side equals 3x+4 and the area equals 15x^2 - x - 28

Algebra ->  Equations -> SOLUTION: I am being asked to find one side of a rectangle when one side equals 3x+4 and the area equals 15x^2 - x - 28       Log On


   

Question 889453: I am being asked to find one side of a rectangle when one side equals 3x+4 and the area equals 15x^2 - x - 28
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
Note that (3x+4) is one factor of 15x^2 -x -28, the other factor will the other side of the rectangle. Also note that the area of a rectangle = length * width
therefore
(3x+4)*(5x-7) = 15x^2 -x -28
thus
5x-7 is the expression for the other side of the rectangle