SOLUTION: Graph the parabola: y=(x+2)^2-4 To graph the parabola, plot the vertex and four additional points, two on each side of the vertex. Then click on the graph icon.

Algebra ->  Graphs -> SOLUTION: Graph the parabola: y=(x+2)^2-4 To graph the parabola, plot the vertex and four additional points, two on each side of the vertex. Then click on the graph icon.       Log On


   



Question 889418: Graph the parabola: y=(x+2)^2-4
To graph the parabola, plot the vertex and four additional points, two on each side of the vertex. Then click on the graph icon.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
According to standard form, this vertex is (-2,-4). Pick your other points according to which you like. Try to do simple ones. x=0, x=1, x=-4, whichever else.

graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28x%2B2%29%5E2-4%29

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the parabola: y=(x+2)^2-4
To graph the parabola, plot the vertex and four additional points, two on each side of the vertex. Then click on the graph icon.

y+=+%28x+%2B+2%29%5E2+-+4
From the above equation, vertex of parabola, or (h, k) = (- 2, - 4)
Two x-values to the LEFT of h = - 2 are: -+3_and_-+4, which will give the two points, (- 3, - 3) and (- 4, 0)
Two x-values to the RIGHT of h = - 2 are: -+1_and_0, which will give the two points, (- 1, - 3) and (0, 0)
Use these four points, and the vertex to graph the parabola!