SOLUTION: A ball is thrown upward with an initial velocity of 64 ft/sec from a height 960 ft. Its height h, in feet, after t seconds is given by h(t)=-16t2 +64t+960. After how long will the
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-> SOLUTION: A ball is thrown upward with an initial velocity of 64 ft/sec from a height 960 ft. Its height h, in feet, after t seconds is given by h(t)=-16t2 +64t+960. After how long will the
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Question 889349: A ball is thrown upward with an initial velocity of 64 ft/sec from a height 960 ft. Its height h, in feet, after t seconds is given by h(t)=-16t2 +64t+960. After how long will the ball reach the ground ? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A ball is thrown upward with an initial velocity of 64 ft/sec from a height 960 ft. Its height h, in feet, after t seconds is given by h(t)=-16t2 +64t+960. After how long will the ball reach the ground ?
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ball will reach the ground when (h(t)=0
-16t2 +64t+960=0
-t^2+4t+60=0
(-t+10)(t+6)=0
t=-6(reject)
or
t=10
After how long will the ball reach the ground ? 10 sec
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