SOLUTION: A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height in feet t seconds after launched is given by s= -16
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Question 889348: A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height in feet t seconds after launched is given by s= -16t^2+v0t. Find the time(s) the projectile will (a) reach a height of 192 feet (b) return to the ground when v0=128 feet per second. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height in feet t seconds after launched is given by s= -16t^2+v0t. Find the time(s) the projectile will (a) reach a height of 192 feet (b) return to the ground when v0=128 feet per second.
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s= -16t^2+v0t
s(t) = -16t^2 + v0t
(a) reach a height of 192 feet
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s(t) = -16t^2 + 128t = 192
-16t^2 + 128t = 192
Solve for t, it's just a quadratic.
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-16t^2 + 128t = 0
Even easier.
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This aint rocket science.
