SOLUTION: 1)find the smallest square number which is divisible by 6,12 and 15 2)the opposite angles of a parallelogram are 2x+10 decree and 3x-20 decree.find all the angles of parallelogram

Algebra ->  Finance -> SOLUTION: 1)find the smallest square number which is divisible by 6,12 and 15 2)the opposite angles of a parallelogram are 2x+10 decree and 3x-20 decree.find all the angles of parallelogram      Log On


   



Question 889284: 1)find the smallest square number which is divisible by 6,12 and 15
2)the opposite angles of a parallelogram are 2x+10 decree and 3x-20 decree.find all the angles of parallelogram.
3)the 3 angles of a quadrilateral are in the ratio of 2:3:5 and the fourth angle is 60 decree.find the measure of the first three angles.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
1)find the smallest square number which is divisible by 6,12 and 15
Break the numbers into their prime factorization:

 6 = 2×3
12 = 2×2×3
15 = 3×5

A square number must have an even number of each prime factor.
So it must have two factors each of 2, 3, and 5.  So the smallest
square number is 2×2×3×3×5×5 = 900

2)the opposite angles of a parallelogram are 2x+10 decree and 3x-20 degrees. Find all the angles of parallelogram.
The opposite angles of a parallelogram are equal.  Set them equal and solve:
2x+10 = 3x-20
   30 = x

So one pair of equal opposite angles are 30° each. The other pair of
opposite angles are supplementary to them, so they are 180°-30° or 150° each.
3)the 3 angles of a quadrilateral are in the ratio of 2:3:5 and the fourth angle is 60 decree. Find the measure of the first three angles.
Since the four angles of any quadrilateral have sum 360°, the three angles
in the ratio 2:3:5 have sum 360°-60° or 300°.  Let their constant of 
proportionality be k, then the three angles are 2k, 3k, and 5k

2k+3k+5k = 300°
     10k = 300°
       k = 30°

So the other three angles are 

2k = 2(30°) = 60°  
3k = 3(30°) = 90°
5k = 5(30°) = 150°

Edwin