SOLUTION: i need help describing and correcting the error
(3/x) + 6/(x+3)=8/(x+1)
LCD=x(x+3)(x+1)
3(x+3)(x+1)=6x(x+1)=8
3(x^2+4x+3)+6x^2+6x=8
3x^2+12x+9+6x^2+6x=8
9x^2+18x+1=0
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-> SOLUTION: i need help describing and correcting the error
(3/x) + 6/(x+3)=8/(x+1)
LCD=x(x+3)(x+1)
3(x+3)(x+1)=6x(x+1)=8
3(x^2+4x+3)+6x^2+6x=8
3x^2+12x+9+6x^2+6x=8
9x^2+18x+1=0
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Question 889164: i need help describing and correcting the error
(3/x) + 6/(x+3)=8/(x+1)
LCD=x(x+3)(x+1)
3(x+3)(x+1)=6x(x+1)=8
3(x^2+4x+3)+6x^2+6x=8
3x^2+12x+9+6x^2+6x=8
9x^2+18x+1=0