SOLUTION: Help please.If k is a negative number, then which of the following equations will have two imaginary solution? (a) (x+1)^2=-k (b)2x^2+5k=0 (c)(x-5)^2=k=0 (d) k-3x^2=0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Help please.If k is a negative number, then which of the following equations will have two imaginary solution? (a) (x+1)^2=-k (b)2x^2+5k=0 (c)(x-5)^2=k=0 (d) k-3x^2=0      Log On


   

Question 889047: Help please.If k is a negative number, then which of the following equations will have two imaginary solution? (a) (x+1)^2=-k (b)2x^2+5k=0 (c)(x-5)^2=k=0 (d) k-3x^2=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
(x+1)^2=-k will have real solutions since k < 0 leads to -k > 0

So choice A is out.

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2x^2+5k=0

2x^2=-5k

will have real solutions since -5k is also positive (same reasoning as A)

choice B is out

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There's a typo in choice C

You wrote (x-5)^2=k=0

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k-3x^2=0

3x^2 = k

this leads to two imaginary solutions since k < 0