SOLUTION: FIVE Years hence, a boys age will four times the square of his age nine years ago. how old is the boy now?

Algebra ->  Finance -> SOLUTION: FIVE Years hence, a boys age will four times the square of his age nine years ago. how old is the boy now?       Log On


   

Question 889019: FIVE Years hence, a boys age will four times the square of his age nine years ago.
how old is the boy now?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
FIVE Years hence, a boys age will four times the square of his age nine years ago.
how old is the boy now?
----------------------------
Equation:
Let his age "x"::
x + 5 = 4(x-9)^2
x + 5 = 4[x^2 - 18x + 81]
x + 5 = 4x^2 - 72x + 324
4x^2 -73x + 319 = 0
-----------------
x = 11 years
------------------
Cheers,
Stan H.
=====================