SOLUTION: We have 3 test score (60+70+80) and we have taken 5 total test. We know the average of our test scores is 80. How do we find out the other 2 test scores?

Algebra ->  Average -> SOLUTION: We have 3 test score (60+70+80) and we have taken 5 total test. We know the average of our test scores is 80. How do we find out the other 2 test scores?      Log On


   



Question 889012: We have 3 test score (60+70+80) and we have taken 5 total test. We know the average of our test scores is 80. How do we find out the other 2 test scores?
Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
We have 3 test score (60+70+80) and we have taken 5 total test. We know the average of our test scores is 80. How do we find out the other 2 test scores?
------
1st test score: x
2nd test score: y
--------
Equatiion:
(60+70+80+x+y)/5 = 80
210 + x + y = 400
x+y = 190
------
That is as far as you can go.
The sum of the unknown test scores must be 190.
Cheers,
Stan H.
----------------

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
We have 3 test score (60+70+80) and we have taken 5 total test. We know the average of our test scores is 80. How do we find out the other 2 test scores?**
***
let x=average of other 2 test scores
%2860%2B70%2B80%2B2x%29%2F5=80
210+2x=5*80=400
2x=190
x=95
average of other 2 test scores=95