SOLUTION: Can you please explain in detail for me...Thank You... 2/{{{y^2-7y+12}}} - 1/{{{y^2-9}}} = 4/{{{y^2-y-12}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Can you please explain in detail for me...Thank You... 2/{{{y^2-7y+12}}} - 1/{{{y^2-9}}} = 4/{{{y^2-y-12}}}      Log On


   

Question 88895: Can you please explain in detail for me...Thank You...
2/y%5E2-7y%2B12 - 1/y%5E2-9 = 4/y%5E2-y-12
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2/{y^2-7y+12} - 1/{y^2-9} = 4/{y^2-y-12}
Factor where you can to get:
[2/[(y-3)(y-4)] - 1/[(y-3)(y+3)] = 4/[(y-4)(x+3)]
Multiply thru by (y-3)(y-4)(y+3) to get:
2(y+3) - [y-4] = 4(y-3)
2y+6-y+4 = 4y-12
3y=22
y= 22/3
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Cheers,
Stan H.