SOLUTION: I need help figuring this out. Thank you. Solve 2 sin^2 a-5 sin a-3=0 in the interval 0° <= m(a)< 360°

Algebra ->  Equations -> SOLUTION: I need help figuring this out. Thank you. Solve 2 sin^2 a-5 sin a-3=0 in the interval 0° <= m(a)< 360°      Log On


   

Question 888891: I need help figuring this out. Thank you.
Solve 2 sin^2 a-5 sin a-3=0 in the interval 0° <= m(a)< 360°
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let x=sin%28a%29
2x%5E2-5x-3=0
%28x-3%29%282x%2B1%29=0
Two solutions:
x-3=0
x=3
sin%28a%29=3
Not a valid solution.
.
.
.
2x%2B1=0
2x=-1
x=-1%2F2
sin%28a%29=-1%2F2
a=210 degrees and a=330 degrees