Question 88888: How many liters of an 11% alcohol solution should be mixed with 60 liters of a 5% alcohol solution to obtain a mixture that is 7% alcohol? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many liters of an 11% alcohol solution should be mixed with 60 liters of a 5% alcohol solution to obtain a mixture that is 7% alcohol?
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Amt of 5% solution = 60 L ; amt of active ingredient = 0.05*60 = 3 L
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Amt of 11% solution = x L ; amt of active ingredient = 0.11x L
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Amt of 7% mixture = (60+x) L ; Amt of active ingre = 0.07(60+x) = 4.2+0.07x L
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EQUATION:
active + active = active
3 + 0.11x = 4.2+0.07x
0.04x = 1.2
x = 30 liters (amt of 11% solution that must be mixed)
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Cheers,
Stan H.
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