Question 888782:  Find the area of the triangle with vertices A(6,-7), B(11,-3) and  
C(2,-2). 
 Answer by Alan3354(69443)      (Show Source): 
You can  put this solution on YOUR website! Find the area of the triangle with vertices A(6,-7), B(11,-3) and  
C(2,-2). 
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x: 6 11 +2 +6 
y:-7 -3 -2 -7 
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Add the diagonal products starting at the upper left. 
-18 - 22 - 14 = -54 
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Add the diagonal products starting at the lower left. 
-77 - 6 - 12 = -95 
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Area = 1/2 the difference = 41/2 
Area = 20.5 sq units
 
 
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