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| Question 888782:  Find the area of the triangle with vertices A(6,-7), B(11,-3) and
 C(2,-2).
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! Find the area of the triangle with vertices A(6,-7), B(11,-3) and C(2,-2).
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 x: 6 11 +2 +6
 y:-7 -3 -2 -7
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 Add the diagonal products starting at the upper left.
 -18 - 22 - 14 = -54
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 Add the diagonal products starting at the lower left.
 -77 - 6 - 12 = -95
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 Area = 1/2 the difference = 41/2
 Area = 20.5 sq units
 
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