SOLUTION: find two numbers such that one number is 5 greater than the other number. If the sum of their squares is 5 times the square of half the smaller number, what are the numbers?
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Question 888659: find two numbers such that one number is 5 greater than the other number. If the sum of their squares is 5 times the square of half the smaller number, what are the numbers? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let one number be x
the other will be x+5
x^2+(x+5)^2 = 5(x/2)^2
x^2+x^2+10x+25=5x^2/4
multiply equation by 4
4x^2+4x^2+40x+100 = 5x^2
3x^2+40x+100=0
3x^2+30x+10x+100=0
3x(x+10)+10(x+10)=0
(x+10)(3x+10)=0
x=-10 OR -10/3
if x= -10
then x+5 =-5
The numbers are -10,-5
-10/3 , 5/3
