SOLUTION: How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8% alcohol solution?

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8% alcohol solution?       Log On


   

Question 888414: How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8% alcohol solution?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8% alcohol solution?
***
let x=amt of 10% solution to mix
40-x=amt of 5% solution to mix
..
10%x+5%(40-x)=8%*40
.10x++2-.05x=3.2
.05x=1.2
x=24
40-x=16
amt of 10% solution to mix=24 liters
amt of 5% solution to mix=16 liters