SOLUTION: Find the percentile rank of 30 in a normal distribution, when the population mean is 18 and the population standard deviation is 1.9.
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Question 888336: Find the percentile rank of 30 in a normal distribution, when the population mean is 18 and the population standard deviation is 1.9. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the percentile rank of 30 in a normal distribution, when the population mean is 18 and the population standard deviation is 1.9.
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z(30) = (30-18)/1.9 = 6.316
P(x < 30) = P(z < 6.316) = 99.9%
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Cheers,
Stan H.
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