Question 888334: Can you help me with the following:
34% of all pets sold at a pet store are dogs. One day, 9 people arrive at the store and purchase pets. (one pet per person)
a)What is the probability that exactly 4 of them are dogs?
b) If the store has only 7 dogs, what is the probability that they have sufficient dogs for sale that day?
thanks Paul
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Can you help me with the following:
34% of all pets sold at a pet store are dogs. One day, 9 people arrive at the store and purchase pets. (one pet per person)
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Binomial Problem with n = 9 and p(buy dog) = 0.34
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a)What is the probability that exactly 4 of them are dogs?
P(x = 4) = 9C4*0.34^4*0.66^5 = binompdf(9,0.34,4) = 0.2109
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b) If the store has only 7 dogs, what is the probability that they have sufficient dogs for sale that day?
P(x <=7) = binomcdf(9,0.34,7) = 9C7*0.34^7*0.66^2 = 0.9989
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I've listed the formula and the TI-84 entry for a and for b.
Cheers,
Stan H.
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Cheers,
Stan H.
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