SOLUTION: if the perimeter of a rectangle with adjacent side lengths of x and y,where x>y, is 8 times as great as the shorter side of the rectangle.what is the ratio of y to x?

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Question 888249: if the perimeter of a rectangle with adjacent side lengths of x and y,where x>y,
is 8 times as great as the shorter side of the rectangle.what is the ratio of y to x?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
That means 2x%2B2y=8%2Ay because y%3Cx, so y is the shorter side.

2x%2B2y-2y=8y-2y
2x%2B0=6y
2x%2Fx=6y%2Fx
2=6y%2Fx
2%2F6=6y%2F%28x%2A6%29
1%2F3=y%2Fx
or the reciprocals
3=x%2Fy

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

if the perimeter of a rectangle with adjacent side lengths of x and y,where x>y,
is 8 times as great as the shorter side of the rectangle.what is the ratio of y to x?


Ratio of y:x: highlight_green%28highlight_green%281%3A3%29%29

You can do the check!! 



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