SOLUTION: Question 1= If Sinθ = 12/13, find the value of Sin^2 θ-cos^2 θ/ 2sinθ cosθ * 1/tan^2 θ
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-> SOLUTION: Question 1= If Sinθ = 12/13, find the value of Sin^2 θ-cos^2 θ/ 2sinθ cosθ * 1/tan^2 θ
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You can put this solution on YOUR website! Question 1= If Sinθ = 12/13, find the value of Sin^2 θ-cos^2 θ/ 2sinθ cosθ * 1/tan^2 θ
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Find the cosine
tan = sin/cos
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The rest is substitution.
Some parentheses are needed to eliminate ambiguities.
