SOLUTION: Emma paid the $9.93 bill for her lunch with 226 coins consisting of pennies, nickels and dimes. If the number of nickels plus the number of dimes was equal to the number of pennies

Algebra ->  Expressions-with-variables -> SOLUTION: Emma paid the $9.93 bill for her lunch with 226 coins consisting of pennies, nickels and dimes. If the number of nickels plus the number of dimes was equal to the number of pennies      Log On


   

Question 888019: Emma paid the $9.93 bill for her lunch with 226 coins consisting of pennies, nickels and dimes. If the number of nickels plus the number of dimes was equal to the number of pennies, then how many coins of each type did she use?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
p+5n+10d=993
p+n+d=226
n+d=p
n=50 d=63 p=113