SOLUTION: The length of a rectangle is seven feet more than its width if the perimete is 18 feet what are its dimensions

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Question 887750: The length of a rectangle is seven feet more than its width if the perimete is 18 feet what are its dimensions
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
L=w+7, 2w+2L=18.

L-w=7 and 2L+2w=18
OR
L-w=7 and L+w=9. Now this can be used right-away in the Elimination Method.