Question 88769: If doris lives to be 100, her age will be 8 less than 4 times her wedding-day age. How old was she when she was married?
Answer by bucky(2189)   (Show Source):
You can put this solution on YOUR website! Given:
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At the age of 100, Doris will be 8 less than 4 times her wedding-day age.
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In other words, 4 times her wedding-day age take away 8 should equal 100. If her wedding-day
age is represented by W, then in equation form:
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4W - 8 = 100
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Add 8 to both sides to get rid of the 8 on the left side and you have:
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4W = 108
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Solve for W, her wedding-day age, by dividing both sides by 4 which is the multiplier
of W. When you do that division you get:
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W = 108/4 = 27
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Doris was 27 when she got married.
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Hope this helps you to understand the problem. Lots of time the wording of problems
such as these is just a little difficult to understand. Once you get the idea of the
relationship, the math is pretty standard. All it takes is a little practice.
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Cheers!
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