SOLUTION: two years ago, a woman was seven times as old as her daughter but in three years she would be only four times as old as her daughter. how old are they now?

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Question 887677: two years ago, a woman was seven times as old as her daughter but in three years she would be only four times as old as her daughter. how old are they now?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w for woman's age
d for daughter's age

Two Years Ago: w-2=7%28d-2%29
w-2=7d-14
w-7d=2-14
w-7d=-12
highlight%287d-w=12%29

In Three Years: w%2B3=4%28d%2B3%29
w%2B3=4d%2B12
w=4d%2B9
highlight%28w-4d=9%29

Two equations in d and w. Solve both for w and equate the expressions, and solve for the value
of d. Find w from the now found d.