Solve for x:
2^(3x-1) = 4^(2x)
I used logarithms to start this problem but I'm having trouble simplifying the problem. Here is what I have been able to do so far.
log2^(3x-1) = log4^(2x)
(3x-1)log2 = (2x)log4
(3x-1)= (2x)log4/log2
You could very well use logs, but it's so much easier to use exponents, and not nearly as confusing. Thus, we have:

------ Converting right-side to similar base: base 2

3x - 1 = 4x ----- Bases are equal, and so are their exponents
3x - 4x = 1
- x = 1


You can do the check!!
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