SOLUTION: Find the product (x – y)(x² + 2xy – y²) (3x – 2)(2x² + 3x – 1) (x³ + 3x² + 1)(3x² + 6x – 2) (x² + 9x + 7)(3x² + 9x + 5)

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the product (x – y)(x² + 2xy – y²) (3x – 2)(2x² + 3x – 1) (x³ + 3x² + 1)(3x² + 6x – 2) (x² + 9x + 7)(3x² + 9x + 5)      Log On


   

Question 887425: Find the product
(x – y)(x² + 2xy – y²)
(3x – 2)(2x² + 3x – 1)
(x³ + 3x² + 1)(3x² + 6x – 2)
(x² + 9x + 7)(3x² + 9x + 5)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the product
(x – y)(x² + 2xy – y²)
= x%2A%28x%5E2+%2B+2xy+-+y%5E2%29+-+y%2A%28x%5E2+%2B+2xy+-+y%5E2%29
= x%5E3+%2B+2x%5E2y+-+xy%5E2+-+x%5E2y+-+2xy%5E2+%2B+y%5E3
= x%5E3+%2B+x%5E2y+-+3xy%5E2+%2B+y%5E3
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Do these the same way.
Use ^ for exponents, not the superscripts.
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(3x – 2)(2x² + 3x – 1)
(x³ + 3x² + 1)(3x² + 6x – 2)
(x² + 9x + 7)(3x² + 9x + 5)