SOLUTION: A pharmacist has two suppliers of vitamin supplements. The strong brand contains 25% vitamin B and 15% vitamin C. The healthy brand contains 15% vitamin B and 20% vitamin c. How ma

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Question 887359: A pharmacist has two suppliers of vitamin supplements. The strong brand contains 25% vitamin B and 15% vitamin C. The healthy brand contains 15% vitamin B and 20% vitamin c. How many milligrams of each brand should the pharmacist use make a mixture that contains 117.5 mg of vitamin B and 120 mg of vitamin C?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = mg of strong brand needed
Let +y+ = mg of healthy brand needed
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+.25x+ = mg of vitamin B in +x+ mg of strong brand
+.15x+ = mg of vitamin C in +x+ mg of strong brand
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+.15y+ = mg of vitamin B in +y+ mg of healthy brand
+.2y+ = mg of vitamin C in +y+ mg of healthy brand
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(1) +.25x+%2B+.15y+=+117.5+
(2) +.15x+%2B+.2y+=+120+
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(1) +25x+%2B+15y+=+11750+
(2) +15x+%2B+20y+=+12000+
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Divide both equations by +5+
(1) +5x+%2B+3y+=+2350+
(2) +3x+%2B+4y+=+2400+
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Multiply both sides of (1) by +4+
Multiply both sides of (2) by +3+
Then subtract (2) from (1)
(1) +20x+%2B+12y+=+9400+
(2) +-9x+-+12y+=+-7200+
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+11x+=+2200+
+x+=+200+
and
(2) +3x+%2B+4y+=+2400+
(2) +3%2A200+%2B+4y+=+2400+
(2) +4y+=+2400+-+600+
(2) +4y+=+1800+
(2) +y+=+450+
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200 mg of strong brand is needed
450 mg of healthy brand is needed
---------------------------------
check:
(1) +.25x+%2B+.15y+=+117.5+
(1) +.25%2A200+%2B+.15%2A450+=+117.5+
(1) +50+%2B+67.5+=+117.5+
(1) +117.5+=+117.5+
OK
You can check the other equation