SOLUTION: Redundancy in Aircraft Radios: The FAA requires that commercial aircraft used for flying in instrument conditions must have two independent radios instead of one. Assume that for a

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Question 887130: Redundancy in Aircraft Radios: The FAA requires that commercial aircraft used for flying in instrument conditions must have two independent radios instead of one. Assume that for a typical flight, the probability of a radio failure is 0.0035. What is the probability that a particular flight will be safe with at least one working radio? Why does the usual rounding rule of three significant digits not work here? Is this probability high enough to ensure flight safety?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
if the probability that one of them will fail is .0035 then the probability that both will fail at the same time is .0035 * .0035 = 1.22 * 10^-5 which is equal to .00001225
if you round to 3 decimal places, your answer will be .000 which doesn't capture the essence of what the data is trying to tell you very well.
while .00001225 is very small, it is not 0.