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| Question 887128:  I.	Given the following polynomial:  2x^2+7x-15=0 .  Check all that apply.
 	The value of the discriminant is 169.
 	There are 2 real roots.
 	There are 2 irrational roots.
 	The graph intersects the y-axis twice.
 	The parabola is directed upward.
 	The axis of symmetry is located at  x=-7/4
 	The vertex is located at:   (-7/4, -49/8)
 	The roots are:  (5,3/2)
 	The graph intersects the y axis at (0, -15).
 	The graph intersects the x-axis at (-5, 0) and (1.5, 0)
 HELP PLEASE
 Found 2 solutions by  josgarithmetic, MathTherapy:
 Answer by josgarithmetic(39630)
      (Show Source): 
You can put this solution on YOUR website! Many of the questions depend on the discriminant. 
  Discriminant is
  . What do you understand about the discriminant for a quadratic expression?
 
 Something about the discriminant indicates that your quadratic expression is factorable.
Answer by MathTherapy(10556)
      (Show Source): 
You can put this solution on YOUR website! I.	Given the following polynomial:  2x^2+7x-15=0 .  Check all that apply. 	The value of the discriminant is 169.
 	There are 2 real roots.
 	There are 2 irrational roots.
 	The graph intersects the y-axis twice.
 	The parabola is directed upward.
 	The axis of symmetry is located at  x=-7/4
 	The vertex is located at:   (-7/4, -49/8)
 	The roots are:  (5,3/2)
 	The graph intersects the y axis at (0, -15).
 	The graph intersects the x-axis at (-5, 0) and (1.5, 0)
 HELP PLEASE
 
 
  , or 
  
     The value of the discriminant is 169. Discriminant:
  , or  ___49 + 120 = 169 (CHECK)   There are 2 real roots. Since the value of DISCRIMINANT (169) > 0, then there are 2 REAL roots. (CHECK)
   There are 2 irrational roots. Since the value of the DISCRIMINANT (169) is a perfect square (
  ), roots are RATIONAL (NO CHECK)
   The graph intersects the y-axis twice. Substituting 0 for x in
  results in y being – 15. The graph has a sole y-intercept, at – 15 (NO CHECK)
   The parabola is directed upward. Since a > 0, the parabola opens upwards. (CHECK)
   The axis of symmetry is located at x =
  . Axis of symmetry is at  , or  , or  (CHECK)   The vertex is located at: (
  ,  ). Substituting  for x in  produces:  , or
  , or  , or  , or  (NO CHECK)   The roots are: (5,3/2)____
  factors to (2x - 3)(x + 5) = 0, so roots are:  and  (NO CHECK)   The graph intersects the y axis at (0, -15). The y-intercept was found to be – 15, so y-intercept is (0, - 15).
 This is a CHECK.
   The graph intersects the x-axis at (-5, 0) and (1.5, 0). As seen above, roots are
  , so the graph intersects the x-axis at (
  ,  ) and (  ,  ). This is a CHECK.
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