Question 887128: I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.
The value of the discriminant is 169.
There are 2 real roots.
There are 2 irrational roots.
The graph intersects the y-axis twice.
The parabola is directed upward.
The axis of symmetry is located at x=-7/4
The vertex is located at: (-7/4, -49/8)
The roots are: (5,3/2)
The graph intersects the y axis at (0, -15).
The graph intersects the x-axis at (-5, 0) and (1.5, 0)
HELP PLEASE
Found 2 solutions by josgarithmetic, MathTherapy: Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! Many of the questions depend on the discriminant.

Discriminant is .
What do you understand about the discriminant for a quadratic expression?
Something about the discriminant indicates that your quadratic expression is factorable.
Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website! I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.
The value of the discriminant is 169.
There are 2 real roots.
There are 2 irrational roots.
The graph intersects the y-axis twice.
The parabola is directed upward.
The axis of symmetry is located at x=-7/4
The vertex is located at: (-7/4, -49/8)
The roots are: (5,3/2)
The graph intersects the y axis at (0, -15).
The graph intersects the x-axis at (-5, 0) and (1.5, 0)
HELP PLEASE
, or

The value of the discriminant is 169. Discriminant: , or ___49 + 120 = 169 (CHECK)
There are 2 real roots. Since the value of DISCRIMINANT (169) > 0, then there are 2 REAL roots. (CHECK)
There are 2 irrational roots. Since the value of the DISCRIMINANT (169) is a perfect square ( ), roots
are RATIONAL (NO CHECK)
The graph intersects the y-axis twice. Substituting 0 for x in results in y being – 15. The
graph has a sole y-intercept, at – 15 (NO CHECK)
The parabola is directed upward. Since a > 0, the parabola opens upwards. (CHECK)
The axis of symmetry is located at x = . Axis of symmetry is at , or , or (CHECK)
The vertex is located at: ( , ). Substituting for x in produces: ,
or , or , or , or (NO CHECK)
The roots are: (5,3/2)____ factors to (2x - 3)(x + 5) = 0, so roots are: and (NO CHECK)
The graph intersects the y axis at (0, -15). The y-intercept was found to be – 15, so y-intercept is (0, - 15).
This is a CHECK.
The graph intersects the x-axis at (-5, 0) and (1.5, 0). As seen above, roots are , so the graph
intersects the x-axis at ( , ) and ( , ). This is a CHECK.
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