SOLUTION: I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.  The value of the discriminant is 169.  There are 2 real roots.  There are 2

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.  The value of the discriminant is 169.  There are 2 real roots.  There are 2       Log On


   



Question 887128: I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.
 The value of the discriminant is 169.
 There are 2 real roots.
 There are 2 irrational roots.
 The graph intersects the y-axis twice.
 The parabola is directed upward.
 The axis of symmetry is located at x=-7/4
 The vertex is located at: (-7/4, -49/8)
 The roots are: (5,3/2)
 The graph intersects the y axis at (0, -15).
 The graph intersects the x-axis at (-5, 0) and (1.5, 0)
HELP PLEASE

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Many of the questions depend on the discriminant.
ax%5E2%2Bbx%2Bc=0
Discriminant is b%5E2-4%2Aa%2Ac.
What do you understand about the discriminant for a quadratic expression?

Something about the discriminant indicates that your quadratic expression is factorable.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.
 The value of the discriminant is 169.
 There are 2 real roots.
 There are 2 irrational roots.
 The graph intersects the y-axis twice.
 The parabola is directed upward.
 The axis of symmetry is located at x=-7/4
 The vertex is located at: (-7/4, -49/8)
 The roots are: (5,3/2)
 The graph intersects the y axis at (0, -15).
 The graph intersects the x-axis at (-5, 0) and (1.5, 0)
HELP PLEASE

2x%5E2+%2B+7x+-+15+=+0, or
0+=+2x%5E2+%2B+7x+-+15
y+=+ax%5E2+%2B+bx+%2B+c
 The value of the discriminant is 169. Discriminant: b%5E2+-+4ac, or 7%5E2+-+4%282%29%28-15%29___49 + 120 = 169 (CHECK)
 There are 2 real roots. Since the value of DISCRIMINANT (169) > 0, then there are 2 REAL roots. (CHECK)
 There are 2 irrational roots. Since the value of the DISCRIMINANT (169) is a perfect square (13%5E2), roots
are RATIONAL (NO CHECK)
 The graph intersects the y-axis twice. Substituting 0 for x in 2x%5E2+%2B+7x+-+15 results in y being – 15. The
graph has a sole y-intercept, at – 15 (NO CHECK)
 The parabola is directed upward. Since a > 0, the parabola opens upwards. (CHECK)
 The axis of symmetry is located at x = -+7%2F4. Axis of symmetry is at x+=+-+b%2F2a, or x+=+-+7%2F%282%2A2%29, or -+7%2F4 (CHECK)
 The vertex is located at: (-+7%2F4, -+49%2F8). Substituting -+7%2F4 for x in 2x%5E2+%2B+7x+-+15 produces: 2%28-+7%2F4%29%5E2+%2B+7%28-+7%2F4%29+-+15,
or 2%2849%2F16%29+-+49%2F4%29+-+15, or 49%2F8+-+49%2F4+-+15, or 49%2F8+-+98%2F8+-+120%2F8, or -+169%2F8 (NO CHECK)
 The roots are: (5,3/2)____2x%5E2+%2B+7x+-+15+=+0 factors to (2x - 3)(x + 5) = 0, so roots are: x+=+3%2F2 and x+=+-+5 (NO CHECK)
 The graph intersects the y axis at (0, -15). The y-intercept was found to be – 15, so y-intercept is (0, - 15).
This is a CHECK.
 The graph intersects the x-axis at (-5, 0) and (1.5, 0). As seen above, roots are %283%2F2%29_and_-+5, so the graph
intersects the x-axis at (3%2F2, 0) and (-+5, 0). This is a CHECK.