Question 886928: Find two solutions of the equation. Give your answers in degrees and radians.
(a) cos theta = sqrt2/2 (b) cos theta = -sqrt2/2
I just don't seem to understand how to even approach this question..
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find two solutions of the equation. Give your answers in degrees and radians.
(a) cos theta = sqrt2/2 (b) cos theta = -sqrt2/2
***
In the first case(a), theta is in quadrant I or IV, in which cos>0.
So, theta=45˚and π/4, or 315˚and 7π/4
..
In the second case(b), theta is in quadrant II or III, in which cos<0.
So, theta=135˚and 3π/4, or 225˚and 5π/4
|
|
|
