SOLUTION: A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 35°
F. After t minutes, the temperature T of the soda is given by T(t) = 35 + 48e^
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-> SOLUTION: A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 35°
F. After t minutes, the temperature T of the soda is given by T(t) = 35 + 48e^
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Question 886776: A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 35°
F. After t minutes, the temperature T of the soda is given by T(t) = 35 + 48e^
– 0.058 t
Find the temperature of the soda 15 minutes after it is placed in the refrigerator. (Round to the
nearest tenth of a degree.)
You can put this solution on YOUR website! A can of soda at 83° F. is placed in a refrigerator that maintains a constant temperature of 35°
F. After t minutes, the temperature T of the soda is given by
T(t) = 35 + 48e^0.058 t
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Find the temperature of the soda 15 minutes after it is placed in the refrigerator. (Round to the nearest tenth of a degree.)
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T(15) = 35 + 48*e^(0.058*15)
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T(15) = 35 + 48*2.3869
T(15) = 35 + 114.57
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Note:: That answer is nonsense. The termperature should
be lower than 83 degrees after being the fridge for 15 minutes.
Please check your problem statement.
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Cheers,
Stan H.
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