SOLUTION: Suppose that the daily % return on a Microsoft share during 2013 has a normal distribution with mean 0.241 and standard deviation 1.8.What is the probability that the daily return
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Question 886687: Suppose that the daily % return on a Microsoft share during 2013 has a normal distribution with mean 0.241 and standard deviation 1.8.What is the probability that the daily return will exceed 2% on a given day. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Suppose that the daily % return on a Microsoft share during 2013 has a normal distribution with mean 0.241 and standard deviation 1.8.What is the probability that the daily return will exceed 2% on a given day.
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z(0.02) = (0.02-0.24)/1.8 = -0.1222
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P(x > 0.02) = P(z > -0.1222) = normalcdf(-0.1222,100) = 0.5486
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Cheers,
Stan H.
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