SOLUTION: A certain culture of the bacterium Streptococcus A initially has 9 bacteria and is observed to double every 1.5 hours. Streptococcus A (12,000 × magnification) (a) Fin

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Question 886451: A certain culture of the bacterium Streptococcus A initially has 9 bacteria and is observed to double every 1.5 hours.

Streptococcus A
(12,000 × magnification)
(a) Find an exponential model
n(t) = n02t/a
for the number of bacteria in the culture after t hours.
n(t) =
.
(b) Estimate the number of bacteria after 29 hours. (Round your answer to the nearest whole number.)
. bacteria
(c) When will the bacteria count reach 10,000? (Round your answer to one decimal place.)
t = h

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A certain culture of the bacterium Streptococcus A initially has 9 bacteria and is observed to double every 1.5 hours.
:
Streptococcus A
(12,000 × magnification)
(a) Find an exponential model
n(t) = n02t/a
for the number of bacteria in the culture after t hours.
n(t) = 9*2^(t/1.5)
:
(b) Estimate the number of bacteria after 29 hours. (Round your answer to the nearest whole number.)
N(t) = 9*2^(29/1.5)
using the calc
N(t) = 9 * 660561.5
N(T) = 5,945,053 bacteria, after 29 hrs
:
(c) When will the bacteria count reach 10,000? (Round your answer to one decimal place.)
9*2^(t/1.5) = 10000
find t
2^(t/1.5) = 10000/9
2^(t/1.5) = 1111.1
Use nat logs
t%2F1.5ln(2) = ln(1111.1)
t%2F1.5 = ln%281111.1%29%2Fln%282%29
using a calc
t%2F1.5 = 10.1178
t = 10.1178 * 1.5
t = 15.2 hrs to reach 10000 bacteria