SOLUTION: if 'n' is odd, then prove that (x + 1) is a factor of x^n + 1

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Question 886347: if 'n' is odd, then prove that (x + 1) is a factor of x^n + 1
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
if x+1 is a factor of x^n+1, then x = -1 is a zero of x^n+1
we are given that n is odd so x^n will be -1 and x^n+1 = 0 with x = -1
therefore x+1 is a factor of x^n+1