SOLUTION: Two hikers start walking in opposite directions from the same place at the same time. The hiker heading west is walking 2 kilometers per hour faster than the hiker heading east. If
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Question 886239: Two hikers start walking in opposite directions from the same place at the same time. The hiker heading west is walking 2 kilometers per hour faster than the hiker heading east. If they are 15 kilometers apart after 1.5 hours what is the rate of each hiker? Let x represent the rate of the westbound hiker and let y represent the rate of the eastbound hiker. Found 2 solutions by JulietG, nerdybill:Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website! Distance per hour = 15 km/1.5 kmh, or 10 kmh
X + Y = 10
Y = X + 2 (he is slower by 2)
Substitute the known value of Y from the second equation into the first.
X + Y = 10
X + (X+2) = 10
2X + 2 = 10
2X = 8
X = 4
The slower hiker is traveling 4kmh. Therefore the faster hiker is traveling 6khm.
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Prove it:
Hiker X travels 4 * 1.5 hours, or 6 km
Hiker Y travels 6 * 1.5, or 9 km
6 + 9 = 15 km in 1.5 hours
Success!
You can put this solution on YOUR website! Two hikers start walking in opposite directions from the same place at the same time. The hiker heading west is walking 2 kilometers per hour faster than the hiker heading east. If they are 15 kilometers apart after 1.5 hours what is the rate of each hiker? Let x represent the rate of the westbound hiker and let y represent the rate of the eastbound hiker.
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Let x = rate of westbound hiker
and y = rate of eastbound hiker
.
From: "The hiker heading west is walking 2 kilometers per hour faster than the hiker heading east."
x = y+2 (equation 1)
From: "they are 15 kilometers apart after 1.5 hours" we have
1.5(x+y) = 15 (equation 2)
substitute value of x from equation 1 into equation 2:
1.5(x+y) = 15
1.5(y+2+y) = 15
1.5(2y+2) = 15
2y+2 = 10
2y = 8
y = 4 kph (rate of eastbound hiker)
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rate of westbound hiker:
x = y+2
x = 4+2
x = 6 kph