Question 88616: Write the equation of the line 'L' satisfying the given geometeric conditions.
'L' has y-intercept (0, -3) and is parallel to the line with equation y=(2/3)x + 1
I can find the points (0, -3) and
I know parallel is the same direction as the other line with equal spacing, and, I can find the y = (2/3)x + 1
but
I am unsure of the over all expectations of 'show your work'.
My professor is fussy. I always get the right answers but when I show my work, I can not seem to please his expectations and I am not being given any credit for my work. Thanks!
Answer by dolly(163)   (Show Source):
You can put this solution on YOUR website! Equation of the given line is y = (2/3)x + 1
==> slope of this line =2/3
The required line is parallel to this line.
So slope of the required line = 2/3 [parallel lines have the same slope]
It passes through (0,-3)
So the equation is y-y1 = m(x-x1)
==> (y - (-3)) = (2/3)(x-0)
==> y+3 = (2/3)x
==> y = (2/3)x - 3 is the equation of the required line L
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