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Question 886054: factor the expression: x^3+2x^2-3x-6
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! start with:
x^3 + 2x^2 -3x - 6
separate into 2 sections as shown below:
(x^3 + 2x^2 - (3x + 6)
factor out x^2 from the section on the left and factor out 3 from the section on the right to get:
x^2 * (x + 2) - 3 * (x + 2)
factor out the common term of (x + 2) to get:
(x^2 - 3) * (x + 2)
those are your factors.
theoretically (x^2 - 3) can also be factored as (x - sqrt(3)) * (x + sqrt(3)) but i'm not sure they want you to go that far.
you would get:
(x - sqrt(3)) * (x + sqrt(3)) * (x + 2)
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