SOLUTION: what is the parabola graph of y < x^2+9x=14 y > 3x^2+10x-8?

y>3x^2+10x-8

Graph the bondary graph:

Find x intercepts:

3x^2+10x-8 = 0
(3x-2)(x+4) = 0

x=-2/3,  x= -4

Find y-intercept

y = 3x^2+10x-8
y = 3(0)^2+10(0)-8
y = -8

Find vertex

x = -b/(2a) = -(10)/(2(3)) = -10/6 = -5/3 = -1.6667
y = 3x^2+10x-8
y = 3(-5/3)^2+10(-5/3)-8
y = -49/3 = -16.3333

vertex = (-1.6667,-16.3333  

y > means to draw the boundary graph dotted (because it is not 
part of the solution set) and shade above  " > "  the boundary 
graph.  (Greater than is above, less than is below).



Can't do the other one because there is an = in there by mistake,
and we can't tell whether it was supposed to be a + or a -.

Edwin