SOLUTION: CRA CDs Inc. wants the mean lengths of the "cuts" on a CD to be 154 seconds (2 minutes and 34 seconds). This will allow the disk jockeys to have plenty of time for commercials with
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-> SOLUTION: CRA CDs Inc. wants the mean lengths of the "cuts" on a CD to be 154 seconds (2 minutes and 34 seconds). This will allow the disk jockeys to have plenty of time for commercials with
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Question 885927: CRA CDs Inc. wants the mean lengths of the "cuts" on a CD to be 154 seconds (2 minutes and 34 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10-minute segment. Assume the distribution of the length of the cuts follows the normal distribution with a population standard deviation of 6 seconds. Suppose we select a sample of 23 cuts from various CDs sold by CRA CDs Inc.
a.What can we say about the shape of the distribution of the sample mean
b.What is the standard error of the mean?
c.What percent of the sample means will be greater than 156 seconds?
d.What percent of the sample means will be greater than 149 but less than 156 seconds Answer by oscargut(2103) (Show Source):
You can put this solution on YOUR website! a)
The sample mean has a normal distribution
b)
standard error of the sample mean is: 6/sqrt(23)
You can ask me more at:
mthman@gmail.com
Thanks
