SOLUTION: hi! can you pls. solve this problem.. a garden plot contain 200 sq. ft. if its length is to be twice its width, what should its dimensions be?

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Question 88592: hi!
can you pls. solve this problem..
a garden plot contain 200 sq. ft. if its length is to be twice its width, what should its dimensions be?
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
The area of the rectangular garden plot is given by:
.
Area = Length * Width
.
The problem tells you that the Length is to be two times the Width. If we call the Length L
and the Width W, then we can write:
.
L = 2*W
.
We can now substitute into the Area equation 2*W for Length and W for Width and 200 for
Area. With these substitutions the Area equation becomes:
.
200 = (2*W) * (W)
.
Multiplying out the right side results in:
.
200+=+2W%5E2
.
Divide both sides of this equation by 2 and the equation then becomes:
.
100+=+W%5E2
.
Then take the square root of both sides. The square root of 100 is 10, and the square root
of W squared is just W. So the equation is then:
.
10+=+W
.
You now know that the Width W is 10 ft and since the Length is twice the Width, the Length
must be 2*10 or 20 ft.
.
So the answer to the problem is W = 10 ft and L = 20 ft.
.
When the Length and Width are multiplied, the answer for the Area is 20*10 = 200 sq ft,
just as the problem said it should be, so the answers for L and W check OK.
.
Hope this helps you to understand the problem.