SOLUTION: Solve for x OO E 8x^(5n) = 17 n=1 I get confused with the 5n I started out by taking out the 8 and putting it in front of the E and then dividing both sides by 8.

Algebra ->  Sequences-and-series -> SOLUTION: Solve for x OO E 8x^(5n) = 17 n=1 I get confused with the 5n I started out by taking out the 8 and putting it in front of the E and then dividing both sides by 8.       Log On


   

Question 885870: Solve for x
OO
E 8x^(5n) = 17
n=1

I get confused with the 5n
I started out by taking out the 8 and putting it in front of the E and then dividing both sides by 8.
I was left with x^5n = 17/8
I then used the formula a/(1-r) to try to solve for x
i came up with x^5/(1-x^5)=17/8
I cross-multiplied and came up with 17-17x^5 = 8x^5 which reduced to 17/25 = x^5
So is my answer really (17/25)^(1/5)?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Some effort was needed to figure what you are asking.
You want the sum of 8x%5E%285n%29 from n=1 to n approaching infinity, is equal to 17.

sum%288x%5E%285n%29%2Cn=1%2Coo%29=17

8%2Asum%28x%5E%285n%29%2Cn=1%2Coo%29=17

sum%28x%5E%285n%29%2Cn=1%2Coo%29=17%2F8

You can find a strong hint how you can solve this in this article, under the "Examples" section: http://en.wikipedia.org/wiki/Power_series