SOLUTION: When 2 balanced dice are rolled, there are 36 outcomes. a.) Find the probability that the second dice is 4 or the sum of the dice is 7. b.) Find the probability that the first dic

Here are the 36 dice rolls:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) 

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) 


If we erase all but those with the second dice 4 or the 
sum of the dice is 7: 

                  (1,4)       (1,6)

                  (2,4) (2,5)  

                  (3,4)  

            (4,3) (4,4)  

      (5,2)       (5,4)  

(6,1)             (6,4) 

Count them.  That's 11.  Probability = 11/36.

Here are the 36 dice rolls again:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) 

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) 

I'll erase all but the ones with the first dice 3 or doubles:

(1,1) 

      (2,2)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

                  (4,4)  

                        (5,5) 

                              (6,6)

Count them.  There's also 11 of those.  Probability = 11/36.

Edwin