Question 88570: Find the center, the vertices, and the foci of the ellipse with the given equation. Then draw the graph.
(x+3)squared, over 25 + (y-5)squared, over 36 =1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the center, the vertices, and the foci of the ellipse with the given equation. Then draw the graph.
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[(x+3)^2 / 25] + [(y-5)^2 / 36] =1
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Center at (-3,5)
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a=sqrt36=6
b=sqrt25=5
c^2=a^2-b^2
c^2 = 35-25
c=sqrt10
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Vertices: (-3,5+6) = (-3,11)
..........(-3,5-6) = (-3,-1)
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Foci: (-3,5+sqrt10)
(-3,5-sqrt10)
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Can't graph the ellipse on this site as it is not a function.
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Cheers,
Stan H.
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